3(y-5)/4 - 4y= 3- (y-3)/2
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3(y-5)/4 - 4y= 3- (y-3)/2==
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3(y−5)÷4−4y=3−(y−3)÷2=)3(y−5)−16y=12−2(y−3)=)3y−15−16y=12−2y+6=)−13y−15=−2y+18=)−11y=33=)−y=1133=)y=−3
\huge{\red{\boxed{\boxed{\green{\underline{\sf{\green{y=-3}}}}}}}}y=−3
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