Question

3(y-5) /4y=3-(y-3)/2 solve the equation

Answer 1

3(y-5)/4-4y=3-(y-3)/2
We move all terms to the left:
3(y-5)/4-4y-(3-(y-3)/2)=0
We add all the numbers together, and all the variables
-4y+3(y-5)/4-(3-(y-3)/2)=0
We calculate fractions
-4y+3y/()+(-(3-(y-3)*4)/()=0

We calculate terms in parentheses: +(-(3-(y-3)*4)/(), so:
-(3-(y-3)*4)/(
We multiply all the terms by the denominator
-(3-(y-3)*4)

We calculate terms in parentheses: -(3-(y-3)*4), so:
3-(y-3)*4
determiningTheFunctionDomain -(y-3)*4+3
We multiply parentheses
-4y+12+3
We add all the numbers together, and all the variables
-4y+15
Back to the equation:
-(-4y+15)

We get rid of parentheses
4y-15
Back to the equation:
+(4y-15)

We get rid of parentheses
-4y+3y/()+4y-15=0
We multiply all the terms by the denominator
-4y*()+3y+4y*()-15*()=0
We add all the numbers together, and all the variables
3y-4y*()+4y*()=0.

Answer 2

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