Question

(3) Yash scored 40 marks in a test, getting
3 marks for each right answer and losing
1 mark for each wrong answer. Had
4 marks been awarded for each correct
answer and 2 marks been deducted for
each incorrect answer, then Yash would
have scored 50 marks. How many
questions were there in the test?​

Answer 1

Number of Questions in the test are 20

Step-by-step explanation:

let the number of right answers = x

let the number of wrong answers = y

We can form two equations,

3x - y = 40 ...(1)

4x - 2y =50...(2)

Solving the two equations,

multiply 1. by 2

we get, 6x - 2y = 80

subtract 2. from 1.

(6x-2y=40) - (4x-2y=50)

thus, x = 15

substitute the value of x in either1 1. or 2.

y=5

thus total questions (x+y) = 20

Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let x be the number of right answers and y be the number of wrong answers.

∴ According to the question ,

3x−y=40⟶(i)

and , 2x−y=25⟶(ii)

On substraction : x=15

putting the value of x in ⟶(i)

3(15)−y=40

y=5

∴ Number of right answers=15 answers

Number of wrong answers=5 answers.

Total Number of questions 5+15=20