3 year ago the population of a town was 50000 if the annual increase during three successive years 5%, 4% and 3% respectively what is its present population
Answers
population when increase 5 percent
= 50000x5/100
=2500
population when increase 4percent
50000x4/100
=2000
population when increase 3percent
=50000x3/100
=1500
total population =50000+2500+2000+1500
=56238
hope this helped you
#bebrainly
Answer:
The present population is 56,238
Step-by-step explanation:
The population 3 years ago was 50,000, which in our case is 100%, what we want to know is the number of people living in that area after the first year, when the population increased by 5%. Since the population increased by 5%, we will add the 5% to the 100% ; 100 + 5 = 105%
We will therefore equate as in the following;
50000 = 100%,
105%?
We then cross multiply:
(50000 × 105) ÷ 100
This gives us, 52,500
This was the population in the third year. We are told that the population increased by 4%. In the second year, the 100% population was 52500, what about when it increased by 4%, that is, (100% + 4% )?
So we say, 52500 = 100%,
104%?
We then cross multiply as follows:
(52500 × 104) ÷ 100 = 54600
Thus, the population in the second year is 54,600.
54600 is the 100% population in the second year. We know that the population increased by 3% in the past year, in that ( 100% + 3% )
We therefore work it out as follows
54600 = 100%
103% ?
We then cross multiply
(54600 × 103 ) ÷ 100 = 56,238
56,238 is the present population.