3 year hence the age of two friend will be X and Y years respectively. therefore the sum of their ages two year ago was ...........years.
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Answer:
3 year hence the age of two friend will be X and Y years respectively. therefore the sum of their ages two year ago was X + Y -10 years.
Step-by-step explanation:
3 Year Hence age of one friend = X
Current age of Friend = X - 3
2 Year Before age of that friend = X - 3 - 2 = X - 5
3 Year Hence age of another friend = Y
Current age of That Friend = Y - 3
2 Year Before age of that friend = Y - 3 - 2 = Y - 5
Sum of their ages two year before = X -5 + Y - 5
= X + Y - 10
sum of their ages two year ago was X + Y -10 years
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