Question

3 years ago anita's age was four times the age of smita at that time five years hence anita's age will be twice the age of smita then find their present ages​

Answer 1

Let the age of Anita be m years and age of Smita be n years respectively.

⌑ Three years ago, their ages —

Anita's age = (m – 3)

Smita's age = (n – 3)

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• As Per Question, we've:

Three years ago Anita's age was four times the age of Smita at that time.

☆ 4(Smita's age) = Anita's age

➟ 4(n – 3) = (m – 3)

➟ 4n – 12 = m – 3

➟ m = 4n – 9 ⠀⠀⠀⠀⠀⠀⠀⠀⠀—eq. ( I )

⠀⠀

Five years Hence, Anita's age will be twice the age of Smita.

⌑ After five years, their ages —

Anita's age = (m + 5)

Smita's age = (n + 5)

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⠀⠀

☆ Anita's age = 2(Smita's age)

➟ (m + 5) = 2(n + 5)

➟ m + 5 = 2n + 10

➟ m = 2n + 10 – 5

➟ m = 2n + 5 ⠀⠀⠀⠀⠀⠀⠀⠀⠀—eq. ( II )

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» From eqₙ ( I ) & eqₙ ( II ) :

⇥ 4n – 9 = 2n + 5

⇥ 4n – 2n = 9 + 5

⇥ 2n = 14

⇥ n = 14⁄2

⇥ n = 7

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✇ Putting value of n in eqₙ ( II ) :

⇥ m = 2n + 5

⇥ m = 2(7) + 5

⇥ m = 14 + 5

⇥ m = 19

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∴ Hence, the present age of Anita and Samita are 7 and 19 years respectively.

Answer 2

Answer:

Age of Anita =19

Age of Smita =7

Step-by-step explanation:

Let the age of Anita be X

Let the age of Smita be Y

3 years ago

X-3=4(Y-3)

X=4Y-12+3=4Y-9 (1)

5 years hence

X+5=2(Y+5)

X=2Y+10-5

X=2Y+5 (2)

Now by equation 1&2, we get

4Y-9=2Y+5

4Y-2Y=9+5

2Y=14

Y=7

then put Y=7 in equation 2nd

X=2×7+5

X=14+5

X=19

I hope it will help u