3 years ago father was 5 times as old as his daughter. Sevan years hence father's age is three times the age of his daughter. Find their present ages.
Answers
GIVEN :–
• 3 years ago father was 5 times as old as his daughter.
• Sevan years hence father's age is three times the age of his daughter.
TO FIND :–
• Their present age = ?
SOLUTION :–
• Let the age of daughter = x
• And the age of her father = y
▪︎ According to the first condition –
▪︎ According to the second condition –
• Using eq.(1) –
• Again Using eq.(1) –
▪︎ Hence –
• The Age of daughter = 13 year
• And The age of her father = 53 year
- 3 years ago father was 5 times as old as his daughter .
- Sevan years hence father's age is three times the age of his daughter.
- Their parents age .
Let,
- = P
- = Q
☯︎ According to the question,
ᴄᴀsᴇ - 1
⇒ P - 3 = 5Q - 15
⇒ P = 5Q - 15 + 3
⇒ P = 5Q - 12 ----(1)
ᴄᴀsᴇ - 2
⇛ P + 7 = 3Q + 21
⇛ P = 3Q + 21 - 7
⇛ P = 3Q + 14 -----(2)
☞︎︎︎ Now comparing equation 1 & 2, we get
⇢ 5Q - 12 = 3Q + 14
⇢ 5Q - 3Q = 14 + 12
⇢ 2Q = 26
⇢ Q = 26/2
⇢ Q = 13
The age of the daughter is '13 years' .
☞︎︎︎ Putting the value of 'Q = 13' the equation (1), we get
➝ P = 5 × 13 - 12
➝ P = 65 - 12
➝ P = 53
The age of the father is '53 years' .