Math, asked by negiaditya34p6aezu, 1 year ago

3 years ago, Sonu was 5 years older than Reena. If now he is twice as old as Reena, find their present ages.

Answers

Answered by Sameeiseka
28

let Reema's age be x yrs

sonu age x+5

is sonu 2x+5

reena=?

5x-3

x=5+3=8 reena age

sonu is x+5

sonu 8+5= 13

their present ages are 8 and 13 yrs


negiaditya34p6aezu: Thanks
Answered by windyyork
22

The present ages of Reena and Sonu are 5 years and 10 years respectively.

Step-by-step explanation:

Since we have given that

3 years ago,

age of Reena be 'x'

age of Sonu be 'x+5'

Present age of Reena be 'x+3'.

Present age of Sonu be 'x+5+3' = x+8

According to question, it becomes,

x+8=2(x+3)\\\\x+8=2x+6\\\\8-6=2x-x\\\\2=x

So, the present age of Reena = x+3 = 2+3 = 5 years

Present age of Sonu = x+8 = 2+8 =10 years

Hence, the present ages of Reena and Sonu are 5 years and 10 years respectively.

# learn more:

Reena's father is 26 year younger than reena's grandfather and 29 years older than reena the sum of their ages is 135 years find their present ages

https://brainly.in/question/6794643

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