Question

3 years ago The age of father was 7 times the age of his son,In present The father's age is 5times of the age of his son, what is the present of the son?
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Answer 1

Explanation:

after 3 years son age =x

after 3 years father age=5x

ATQ

5x-3=7x(x-3)

5x-3=7x-21

5x-7x=-21+3

-2x=-18

x=-18/-2

x=9years

so,son age =9 years

father age = 5x9years

=45years

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Answer 2

Answer:

Given

3 years ago The age of father was 7 times the age of his son,In present The father's age is 5times of the age of his son, what is the present of the son?

To find

after 3 years age of the son is =x

after 3 years age of father is =5x ( more five time )

Solution

$= 5x-3=7x(x-3) \\ </p><p> = 5x-3=7x-21 \\ </p><p> = 5x-7x=-21+3 \\ </p><p> = -2x=-18 \\ </p><p> = x=-18/-2$

$</p><p>x=9 \: years \\ </p><p>so, \: age \: of \: son \: is =9 years \\ </p><p>age \: of \: father \: is = 5x9years \\ </p><p>=45years$

I hope it helps