Math, asked by ng355740, 1 year ago

3 years ago, the population of a village was 25000. The rate of growth of population is 3%. But, one year ago , 500 people died of epidemic disease, what is the present population of the village ???

Answers

Answered by panchalshubh2108
5

Answer:

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Answered by brainlysme13
3

The current population of the village is approximately 26803 people.

Given,

population of a village 3 years ago = 25000

rate of growth of population = 3%

no. of people who died due to epidemic an year ago = 500

To Find,

the present population of the village

Solution,

We can solve this problem using a simple method.

We have been given that the population of a village 3 years ago is 25000.

We have also been given that the rate of growth of population each year is 3%

This means that 2 years ago, the population was 25000 + 3% of 25000

⇒ 25000 + 750

⇒ 25750 is the population 2 years ago.

Further an year ago, the population was 25750 + 3% of 25750

⇒ 25750 + 0.03 of 25750

⇒ 25750 + 772.5

⇒ 26522.5 is the population an year ago.

But we have been given that 500 people died of epidemic disease.

⇒ The population was 26522.5 - 500 an year ago.

⇒ Hence, the population was 26022.5 - 500 an year ago.

Now, the current year, the population grew 3%

⇒ 26022.5 + 3% of 26022.5

⇒ 26022.5 + 780.675

⇒ 26803.105 is the present population

Hence, the current population of the village is approximately 26803 people.

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