3 years ago, the ratio of age of a and b is 3: 4. After 2 years, the sum of their ages is 45. Then find the present age of a?
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HELLO MATE
YOUR ANSWER
AGE OF a (3 YEARS AGO)= 3x
AGE OF b (3 YEARS AGO)= 4x
PRESENT AGE OF a = 3x+3
PRESENT AGE OF b = 4x+3
AGE OF a AFTER TWO YEARS =3x+3+2
AGE OF b AFTER TWO YEARS =4x+3+2
NOW, ACCORDING TO THE QUESTION
(3x+3+2)+(4x+3+2)=45
3x+5+4x+5=45
7x+10=45
7x=45-10
7x=35
x=35/7
x=5
THEN
THE PRESENT AGE OF a = 3x+3
=3×5+3
=18
HOPE YOU UNDERSTAND
^-^ ^-^
YOUR ANSWER
AGE OF a (3 YEARS AGO)= 3x
AGE OF b (3 YEARS AGO)= 4x
PRESENT AGE OF a = 3x+3
PRESENT AGE OF b = 4x+3
AGE OF a AFTER TWO YEARS =3x+3+2
AGE OF b AFTER TWO YEARS =4x+3+2
NOW, ACCORDING TO THE QUESTION
(3x+3+2)+(4x+3+2)=45
3x+5+4x+5=45
7x+10=45
7x=45-10
7x=35
x=35/7
x=5
THEN
THE PRESENT AGE OF a = 3x+3
=3×5+3
=18
HOPE YOU UNDERSTAND
^-^ ^-^
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