Question

3 years ago, the sum of ages of a father and his
son was 40 years. After 2 years, the sum of
ages of the father and his son will be ..........
(a) 40 (b) 46 (c) 50 (d) 60​

Answer 1

Step-by-step explanation:

Let father's age be x yrs

sons age be y yrs

according to first condition

(x-3)+(y-3)=40

x-3+y-3=40

x+y-6=40

x+y=40+6

x+y=46..........1

according to second condition

(x+2)+(y+2)=?

x+2+y+2=?

x+y=-4....

from 1 and 2

46=-4

46+4=50

Answer 2

Answer:

option c.

Step-by-step explanation:

let the age of son be s and age of father be f.

now,

we have given that before three years the sum of their ages was 40 yrs.

their ages before 3 yrs :

son = s - 3

father = f - 3

now,

equation we got by this - ( (s - 3) + (y - 3) )

( (s - 3) + (y - 3) ) = 40

s + f - 6 = 40

s + f = 46__ eq2

since we got their present ages sum 46 yrs

age of son = s

age of father = 46 - s__by eq3

now,

sum of their ages after 2 years -

( s + 2 ) + ( f + 2 )

( s +2) + ( 46 - s + 2 ) {by eq 3 - f = 46-s }

s cancelled by s

46 + 2 + 2

= 50 yrs

sum of their ages after 2 yrs will be 50 yrs.