3 years ago the sum of the ages of a father and a son was 40 years. 2 years hence, the sum of their ages will be…..years.
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Let present age of father and son be x and y respectively
then 3 years ago sum of then age is 40.
⇒(x−3)+(y−3)=40
x+y=46⇒y=46−x...(1)
After 2 years ; sum of age of father and son is
Let t=(x+2)+(y+2)
t=(x+2+46−x+2) from (1)
=46+4
t=50
So sum of their ages after 2 years = 50.
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