3 years ago the sum of the ages of father and son was 40 years after 2 years the sum of their ages will be
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Let the age of father be x
Son's age be y
3yrs ago the age of father is x-3; son's age wills be y-3
Sum of their ages 5 yrs ago=40
x-3+y-3=40
x+y-6=40
x+y=46
Age of father after 2yrs will be x+2; son's age will be y+2
Sum of their ages after 2yrs=x+2+y+2
=x+y+4
=46+4=50yrs
Hope it helps!!
Son's age be y
3yrs ago the age of father is x-3; son's age wills be y-3
Sum of their ages 5 yrs ago=40
x-3+y-3=40
x+y-6=40
x+y=46
Age of father after 2yrs will be x+2; son's age will be y+2
Sum of their ages after 2yrs=x+2+y+2
=x+y+4
=46+4=50yrs
Hope it helps!!
wvaish:
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Let the age of father 3 years ago =x
So age of son 3 years ago =(40- x)
Their present ages :-
Father =x+3
Son = (40-x+3) = 43-x
After 2 years their ages :- father = x+3+2 = x+5
Son = 43-x+2 = 45-x
Sum = x+5+45-x =50 years
So age of son 3 years ago =(40- x)
Their present ages :-
Father =x+3
Son = (40-x+3) = 43-x
After 2 years their ages :- father = x+3+2 = x+5
Son = 43-x+2 = 45-x
Sum = x+5+45-x =50 years
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