Question

(3) YH
21. A liquid mixture of volume V, has two liquids as its
ingredients with densities a and B. If density of the
mixture is o, then mass of the first liquid in
mixture is
a V[oß + 1]
aV[o-B1.
To+B]
(1)
Bla + o]
(2)
a V(B-0)
B-a
a V[1-0a]
Bla-o]
(3)
(4)​

Answer 1

Mass of the first liquid in mixture is (M₁) = αV(β-σ)/β-α

Given-

• Volume of the mixture = V
• Density of first ingredient = α
• Density of second ingredient = β
• Density of mixture = σ

Let the mass of first liquid = M₁

Mass of second liquid = M₂

Total mass = M₁ + M₂

We know that density is equals to mass per unit volume.

So,

σ = total mass/ V

Vσ = M₁ + M₂

M₂ = Vσ - M₁  -----------(i)

V is total volume so

V = M₁/α + M₂/β

By substituting the value-

σ = M₁ + M₂ / (M₁/α) + (M₂/β)

Substituting the value of M₂ from equation (i) we get

M₁ = αV(β-σ)/β-α

Answer 2

Answer:

See The Attachment...Hope U Understand