Question

30 - [15 - {8 - (6 - 8 – 7)}] + 14 = 7 and their is a bar at 8-7​

Answer 1

Correct Question :

$\tt{ 30 - [15 - {8 - (6 - \overline{8- 7})}] + 14 }$

Answer :

To solve the given problem ; we will use the BODMAS. It says :

B - Bracket

1. ( )
2. { }
3. [ ]

O - Of

D - Division

M - Multiplication

A - Addition

S - Subtraction

Beside this we need to solve the bar first . So following the information about we will solve the given problem.

Solution :

$\longrightarrow{\tt{ 30 - [15 - {8 - (6 - \overline{8 - 7})}] + 14 }}$

$\longrightarrow{\tt{ 30 - [15 - {8 - (6 - 1)}] + 14 }}$

$\longrightarrow{\tt{ 30 - [15 - {8 - 5}] + 14 }}$

$\longrightarrow{\tt{ 30 - [ 15 - 13] + 14 }}$

$\longrightarrow{\tt{ 30 - 2 + 14 }}$

$\longrightarrow{\tt{ 30 - 16 }}$

$\large{\implies{\boxed{\tt{ 14 }}}}$

Answer 2

$\mathfrak{\huge{\underline{\underline{\green</p><p>{QuEsTiOn:-}}}}}$

✳ 30 - [15 - {8 - (6 - 8 – 7)}] + 14 = 7 and their is a bar at 8-7 .

$\mathcal{\huge{\underline{\underline{\green</p><p>{AnSwEr:-}}}}}$

➡ $\large{\boxed{\tt{ 14 }}}⟹ </p><p>14$

$\mathcal{\huge{\underline{\underline{\pink{SoLuTiOn:-}}}}}$

$\longrightarrow{\tt{ 30 - [15 - {8 - (6 - \overline{8 - 7})}] + 14 }}$

$\longrightarrow{\tt{ 30 - [15 - {8 - (6 - 1)}] + 14 }}$

$\longrightarrow{\tt{ 30 - [15 - {8 - 5}] + 14 }}$

$\longrightarrow{\tt{ 30 -15 [-13] + 14 }}$

$\longrightarrow{\tt{ 30 - [2] + 14 }}$

$\longrightarrow{\tt{ 30 - 2 + 14 }}$

$\longrightarrow{\tt{ 30 - 16 }}$

⟹ 14

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