Question

(3°+2-¹)÷(2)-² plz help fast​

Answer 1

Step-by-step explanation:

Valueof(2

−1

×4

−1

)÷2

−2

= \frac{( 2^{-1} \times 4^{-1} ) }{2^{-2}}=

2

−2

(2

−1

×4

−1

)

= \frac{ 2^{2}}{2^{1} \times 4^{1}}=

2

1

×4

1

2

2

\blue { (By \: Exponential \:Law : )}(ByExponentialLaw:)

\boxed { \pink { a^{-n} = \frac{1}{a^{n}} }}

a

−n

=

a

n

1

\begin{gathered} = \frac { 4}{8} \\=\frac{1}{2} \end{gathered}

=

8

4

=

2

1

Therefore.,

\red { Value \:of \: ( 2^{-1} \times 4^{-1} ) \div 2^{-2}} \green {= \frac{1}{2} }Valueof(2

−1

×4

−1

)÷2

−2

=

2

1

Answer 2

Answer:

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