Question

(30 ‚64) (-1‚3) prove that these vertices are of right angle triangle​

Answer 1

Answer:

AB=√(6-3)^2+(4-0)^2=√9+16=√25=5

BC=√(-7)^2+(-1)^2=√50=5√2

AC=√(-4)^2+(3)^2=√25=5

BC^2=AB^2+BC^2

(5√2)^2=5^2+5^2

GIVEN vertices firm right àngle ∆