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A bag contains 8 white & 4 red balls. five balls are drawn
at random what is the probability that?
of then are red and 3 white
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Answer:
total number of Sample space = 12C5.
No. of way to draw 2 red balls = 4C2
No. of way to draw 3 white balls = 8C3.
Total number of ways to draw 2 red and 3 white balls = 4C2 * 8C3.
Probability that 2 red and 3 white balls are drawn is
= (4C2*8C3)/12C5
= (4*3/2*1)*(8*7*6/3*2*1)*(5*4*3*2*1/12*11*10*9*8)
= 14/33
Explanation:
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