30. A body moving with uniform acceleration describes 76 m in 5th sec. and 116 m in the 10th second. Find the distance covered in 15th second. How far will it go in the next 5 second ? [Ans. 156 m, 900 m]
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Mr Right now I'm not going anywhere
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(u+15a)×t +(1/2)at2 = [40+(15×8)]×5 + (1/2)×8×25 = 900m
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