30. A car travels 6 km towards north at an angle of 45° to the
east and then travels distance of 4 km towards north at an
angle of 135° to the east. How far is the point from the
starting point. What angle does the straight line joining its
initial and final position makes with the east.
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- Net distance traveled along x-direction, Sx = 6 cos 45ºi - 4 cos 45ºi
- 1 = 2 × √2km
- √2
- Net distance traveled along y-direction Sy=6 sin 45° + 4 sin 45ºj
- = = 10 x
- 1 5√2km
- √2
- .. Net distance traveled from the starting point,
- S V S² + S² = √(√2)² + (5√2)²
- = √2+25 × 2 = √52km
- Angle which the resultant makes with the east direction
- tan Ꮎ
- y 5√2 √2 or 0 = tan¹ (5)
- X
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