Question

30. A helicopter is ascending at a rate of 10m/s. At a height of 75m above the ground, a package is dropped.
How long does the package take to reach the ground?​

Answer 1

R.E.F. Image.
U = 8 cm/sec.,a = -g
s =ut+
2
1
​
at
2

−12=8t−
2
1
​
×9t
2

−12=8t−5t
2

5t
2
−8t−12=0
t = 2.53 seconds.
so, option (d)

Answer 2

Answer:

time = distance/speed

take,

speed= 10m/s

and

distance=75m

.

NOW,

Time = 75/10

Time = 7.5 seconds

Explanation:

Hope this helps you.