Question

30.
A particle is projected at a certain angle from the
ground. The gravitational potential energy of the
projectile as a function of time can be best
represented as (assume ground as reference for
zero potential energy). in graph form​

Answer 1

Answer:

Let the velocity and angle be

$u \: \: \: \: and \: \: \: \: \alpha$

Height at some time

$s = ut + \frac{1}{2} a{t}^{2} \\ \\ h = u \sin( \alpha ) t - \frac{1}{2} g {t}^{2}$

So Gravitational potential energy

$= mgh \\ \\ = mg(u \sin( \alpha ) t - \frac{1}{2} g {t}^{2} ) \\ \\ = ugt \sin( \alpha ) - \frac{1}{2} {g}^{2} {t}^{2} \\ \\ g = 10 \\ \\ = 10ut \sin( \alpha ) - 50 {t}^{2}$