Math, asked by mohdrazaullah9312, 3 days ago

30. A piece of wire in the form of an
equilateral triangle of side 31.4 m is bent
into a ring with no loss in wore. Find the
radius of the ring.
(a) 20 m
(b) 25 m
(e) 15 m
(d) 30 m​

Answers

Answered by sarthakgamer651
5

Answer:

30 cm  

Option D

Step-by-step explanation:

One side of equilateral triangle = 31.4 cm  

Perimeter = 31.4 + 31.4 + 31.4 =  3 * 31.4 cm  

Perimeter of circle = Pie * Diameter  

= > 3.14 * Diameter = 3 * 31.4  

=> Diameter = 30 cm

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Answered by prudhvinadh
2

Answer:

approximately 15m but 14.986 m exactly.

Step-by-step explanation:

Given: side of the triangle = 31.4

as same length of wire is used, the perimeter will be same for both triangle and circle.

perimeter of equilateral triangle = perimeter of circle

3 *a = 2π * r ( here a is side of triangle and r is radius)

3 * 31.4 = 2*22/7 * r

r = (3 * 31.4 * 7)/ 44

= 14.986 m ( if used π = 22/7)

≈ 15m ( if used π = 3.14)

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