Question

30. a smooth seeded and red flowered pea plant ( SsRr) is crossed with a smooth seeded and white flowered ( Ssrr pea plant. determine the phenotypic and genotypic ratio's of the F1 progeny?

Answer 1

Hope this helps !
In this,
Genotypic ratio -
1:1:2:2:1:1
Phenotypic ratio-
1:3:3:1
The reasons and everything is given in the picture.

Answer 2

Answer:

This is a dihybrid cross.

Explanation:

• A dihybrid cross is a cross between two organisms that are identical hybrids for two traits in a breeding experiment.
• A dihybrid cross, then, is a union of two organisms that are heterozygous for two separate features. The people that exhibit this type of trait are homozygous for that trait. Genes, which are pieces of DNA, control these qualities.
• Each pair of alleles for each attribute is carried by a different set of parents in a dihybrid cross.
• While the other parent contains the homozygous recessive allele, one parent has the homozygous dominant allele.
• All of the F1 generation's progeny are heterozygous for particular features after the crossings.

• Dominant character = SS (smooth seed), RR (red seed).
• Recessive character = ss (rough seed), rr (white seed).
• On crossing SsRr with Ssrr, the F1 progeny obtained is:

1. SSRr
2. SSrr
3. SsRr
4. Ssrr
5. SsRr
6. Ssrr
7. ssRr
8. ssrr

• The phenotypic ratio = 3:3:1:1
• The genotypic ratio = 1:2:1:2:1:1

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