30. A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have
taken 48 min less for the same journey. Find the speed of the train.
Answers
Time take by the train intially = begin mathsize 12px style 360 over x end style
If the speed was increased by 5km/hr
Time taken by train = begin mathsize 12px style fraction numerator 360 over denominator x plus 5 end fraction end style
Difference in the time taken is 48 minutes,
begin mathsize 12px style fraction numerator 360 over denominator x space end fraction minus space fraction numerator 360 over denominator x plus 5 end fraction space equals space 48 over 60 space space space space space left parenthesis c o n v e r t i n g space 48 m i n s space t o space h o u r s right parenthesis rightwards double arrow 360 open square brackets fraction numerator x plus 5 minus x over denominator x left parenthesis x plus 5 right parenthesis end fraction close square brackets equals 4 over 5 rightwards double arrow 90 open square brackets fraction numerator 5 over denominator x left parenthesis x plus 5 right parenthesis end fraction close square brackets equals 1 fifth rightwards double arrow 90 left square bracket 5 right square bracket 5 equals x squared plus 5 x end style
x2+5x -2250 = 0
(x+50)(x-45)
Speed = 45 km/hr as speed cannot be negative