Math, asked by akanshachauhan06, 2 months ago

30. ABCD is a parallelogram. Find the measure
of angle A,B,C and angle D

Answers

Answered by Anonymous
0

Answer:

Let ABCD be the given parallelogram and ∠A be the given angle.

∴∠A=68°

As we know that, in a parallelogram opposite angles are equal.

∴∠C=∠A=68°

Let the measurement of ∠B be x°.

∴∠D=∠B=x°(∵Opposite angles)

Now as we know that sum of all the angles in a parallelogram is 360°.

∴68°+x°+68°+x°=360°

⇒2x°+136°=360°

⇒2x°=360°−136°

⇒x°=

2

224°

=112°

Hence the measure of all the 4 angles of the parallelogram is 68°,112°,68° and 112°.

Step-by-step explanation:

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Answered by aaronthomas232200
1

Answer:

Let ABCD be the given parallelogram and ∠A be the given angle.

∴∠A=68°

As we know that, in a parallelogram opposite angles are equal.

∴∠C=∠A=68°

Let the measurement of ∠B be x°.

∴∠D=∠B=x°(∵Opposite angles)

Now as we know that sum of all the angles in a parallelogram is 360°.

∴68°+x°+68°+x°=360°

⇒2x°+136°=360°

⇒2x°=360°−136°

⇒x°=

2

224°

=112°

Hence the measure of all the 4 angles of the parallelogram is 68°,112°,68° and 112°.

Step-by-step explanation:

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