30.Angles of a triangle
are
(5x+4), (x-2) and (3x+7). Find all the angles of a triangle
Answers
Answered by
0
Step-by-step explanation:
Sum of 3 angles of a triangle should be equal to 180°
So , sum of (2x-30°) , (3x-40°) and (5/2+10°) should be 180°
(2x-30) + (3x-40) + (5/2+10) = 180
5x - 30 - 40 + 10 + 5/2 = 180
5x - 60 + 5/2 = 180
5x = 180 + 60 - 5/2
5x = 240 - 5/2
5x = 475/2
x = 95/2
x = 47.5
Now the 3 angle of triangle are :
(2x-30) = 2*47.5 - 30 = 65°
(3x-40) = 3*47.5 - 40 = 102.5°
(5/2+10) = 12.5°
Answered by
1
Answer:
Angles of triangle are (5x+4), (x+2) and (3x+7).
Sum of all angles of triangle = 180°
A.T.Q
(5x+4) + (x+2) +(3x+7) = 180°
9x + 13 = 180°
9x = 180°-13
9x = 167
x= 167/9
x = 18.55
First angle = 5x+4
= 5×18.55+4
= 96.75
Second angle = x+2
= 18.55+2
= 20.55
Third angle = 3x+7
= 18.55×3+7
= 62.65
Similar questions