Question

30.Angles of a triangle
are
(5x+4), (x-2) and (3x+7). Find all the angles of a triangle​

Answer 1

Step-by-step explanation:

Sum of 3 angles of a triangle should be equal to 180°

So , sum of (2x-30°) , (3x-40°) and (5/2+10°) should be 180°

(2x-30) + (3x-40) + (5/2+10) = 180

5x - 30 - 40 + 10 + 5/2 = 180

5x - 60 + 5/2 = 180

5x = 180 + 60 - 5/2

5x = 240 - 5/2

5x = 475/2

x = 95/2

x = 47.5

Now the 3 angle of triangle are :

(2x-30) = 2*47.5 - 30 = 65°

(3x-40) = 3*47.5 - 40 = 102.5°

(5/2+10) = 12.5°

Answer 2

Answer:

Angles of triangle are (5x+4), (x+2) and (3x+7).

Sum of all angles of triangle = 180°

A.T.Q

(5x+4) + (x+2) +(3x+7) = 180°

9x + 13 = 180°

9x = 180°-13

9x = 167

x= 167/9

x = 18.55

First angle = 5x+4

= 5×18.55+4

= 96.75

Second angle = x+2

= 18.55+2

= 20.55

Third angle = 3x+7

= 18.55×3+7

= 62.65