Question

30 bulbs are connected in series.If one bulb is fused and the remaining 29 bulbs are joined in series and connected to the same supply,the light in the room will be:


(increased,decreased,remained same)

please...say the correct answer : )

Answer 1

Answer ⇒ The light in the room will be Increased.

Explanation ⇒
If one bulb is fused in the series of 30 bulbs,then 29 bulbs will be left. Thus, Resistance in the series will be Deceasing since the number of bulbs is also decreasing. Now, the current will be increase in each bulbs since, the number of bulbs is decreased.

According to the Ohm's law, Current is directly Proportional to the Potential difference. This means that If the current will increases then the Voltage in each bulbs will also increase. Hence, the light in the room will be increased.


Hope it helps. 

Answer 2

the light in room will increase

let the resistance of each bulb be r

as first 30 bulb connected in series so resistance will be 30 r now one bulb fused left 29 bulbs

these 29 are connected in series

so equivalent resistance = 29 r

if resistance will decrease then current will increase

current directly proportional to potential

on increasing current potential will also increase

brightness of bulb depends upon product of current and potential = v*I

since both v and I are increasing thus brightness will also increase