30. Calcium carbonate reacts with HCl to give CaCl2
and Co, according to the reaction:
Caco,(s) + 2HCl(aq) + CaCl (aq) + CO2(g) +
H2O(1) What mass of 20% impure CaCO3 is
required to react completely with 250 mL of 0.50
M HCI?
(1) 6.25 g
(3) 4.75 g
(2) 5g
(4) 7.8 g
Answers
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Answer:
The mass of HCl is
1000
0.75×36.5
×25=0.684g.
1 mole of calcium carbonate reacts with 2 moles of HCl.
Hence, the mass of calcium carbonate that will react completely with 0.684 g of HCl is
2×36.5
100
×0.684=0.937g.
Explanation:
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