30 Circular plates, each of radius 14 cm and thickness 3 cm are placed above the another to form a cylindrical solid.
(1) find the total surface area
(2) volume of the cylinder w
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Solution :
given,
radius of circular plate (r) = 14 cm
thickness of circular plate = 3 cm
thickness of 30 circular plate = 30×3 = 90 cm
Since,
30 circular plates are placed on above the another to form a cylindrical solid. Then, height of the cylindrical solid, h = thickness of circular plates = 90cm.
(1) Total surface area of the cylindrical solid so formed,
= 2πr(r+h)
= 2×22/7×14(90+14)
= 9152 cm²
Hence, the total surface area of the cylindrical solid is 9152 cm².
(2) Volume of the cylinder so formed,
= πr²h
= 22/7 × (14)² × 90
= 55440 cm³
Hence, the volume of the cylinder so formed is 55440 cm³.
given,
radius of circular plate (r) = 14 cm
thickness of circular plate = 3 cm
thickness of 30 circular plate = 30×3 = 90 cm
Since,
30 circular plates are placed on above the another to form a cylindrical solid. Then, height of the cylindrical solid, h = thickness of circular plates = 90cm.
(1) Total surface area of the cylindrical solid so formed,
= 2πr(r+h)
= 2×22/7×14(90+14)
= 9152 cm²
Hence, the total surface area of the cylindrical solid is 9152 cm².
(2) Volume of the cylinder so formed,
= πr²h
= 22/7 × (14)² × 90
= 55440 cm³
Hence, the volume of the cylinder so formed is 55440 cm³.
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