Question

30 circular plates,each of radius 14cm and thickness 3cm are placed one above the another to form a cylindrical solid.
1)what is the total height of the cylindrical solid?
2)what is the CSA of the cylindrical solid?
3)what is the equation for finding TSA of cylinder with radius 'r' and height 'h'?
4)what is the TSA of the cylindrical solid?
5)what is the volume of the cylindrical solid?​

Answer 1

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Given,

• radius of a circular plate, r = 14 cm
• Thickness of a circular plate = 3 cm
• Thickness of 30 circular plates = 30 x 3 = 90 cm

Since, 30 circular plates are placed one above the another to form a cylindrical solid. Then,

Height of the cylindrical solid, h = Thickness of 30 circular plates = 90 cm

1. Total surface area of the cylindrical solid so formed

= 2πr(h+ r)

= 2 x (22/7) x 14(90+ 14)

= 44 x 2 x 104

= 9152 cm2

Hence, the total surface area of the cylindrical solid is 9152 cm2,

2. Volume of the cylinder so formed

= πr2h = (22/7) (14)2 x 90

= (22/7) x 14 x 14 x 90

= 22 x 28 x 90

= 55440 cm3

Hence, the volume of the cylinder so formed is 55440 cm3.

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Answer 2

Given : 30 circular plates, each of radius 14cm and thickness 3cm are placed one above the another to form a cylindrical solid.

To Find :

1)what is the total height of the cylindrical solid?

2)what is the CSA of the cylindrical solid?

3)what is the equation for finding TSA of cylinder with radius 'r' and height 'h'?

4)what is the TSA of the cylindrical solid?

5)what is the volume of the cylindrical solid?​

Solution:

Thickness of one =  3cm

Thickness of 30 = 30 x 3 = 90 cm

CSA of the cylindrical solid  = 2πrh

= 2(22/7) * 14 * 90

= 7920  cm²

equation for finding TSA of cylinder with radius 'r' and height 'h

= 2πrh +  2πr²

TSA of the cylindrical solid  2πrh +  2πr²

7920  + 2πr²

= 7920  + 2(22/7)(14)²

= 7920  + 1232

= 9152 cm²

volume of the cylindrical solid

= ​πr²h

= (22/7)(14)²90

= 55,440 cm³

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