Math, asked by bindalrachna01, 5 months ago

30. Consider the following frequency distribution of manual workers
Frequency
10
Expenditure (in Rs.)
0-500
500-1000
1000-1500
1500-2000
2000-2500
13
10
15
8
11
Then, find the average expenditure which is done by the maximum number of manuaal workers​

Answers

Answered by priyadpriyadarshini3
0

Answer:

ANSWER

We observe that the class 1500−2000 has the maximum frequency 40.

So, 1500−2000 is a modal class.

l=1500,h=2000−1500=500,f=40,f

1

=24 and f

2

=33

⇒ Mode=l+

2f−f

1

−f

2

f−f

1

×h

=1500+

2×40−24−33

40−24

×500

=1500+

80−57

16

×500

=1500+

23

16

×500

=1500+347.826

=1847.826

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