Question

30 coulombs of charge is brought from infinity to a given point in an electric field when

90 joule of work is done. What is the potential at that point?​

Answer 1

Answer:

W=QV

90 = 30xV

V = 90/30

V = 3

potential of point is 3 V

Answer 2

Answer:

3 V

Explanation:

W=V×Q

90=V×30

V=W÷Q

V=90÷30

V=3