30 electrons are flowing through an electric wire in a time of 3 seconds. Then the amount of current flowing through the wire is ..................
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Answer:
I = 1 . 6 × 10 ^ - 18 .
Explanation:
Q = 30 Electrons .
T = 3 Seconds .
I = ? .
I = Q / t .
I = ne / t .
I = 30 × 1.6 × 10 ^ - 19 / 3 .
Cancel 3 in the denominator with 30.
Where 30 = 10 and 3 = 1.
I = 10 × 1.6 × 10 ^ - 19 .
I = 16 × 10 ^ - 19 .
I = 1 . 6 × 10 ^ - 18 .
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