Question

30. Factorise 1/3x2-2x-9
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Answer 1

Answer:

• (x-9) (x+3)

Step-by-step explanation:

$\implies{\small{\tt{\dfrac{1}{3}x^2 - 2x - 9}}}$

${\implies{\small{\tt{ \dfrac{1}{3} \bigg( x^2 - 6x - 27 \bigg)}}}}$

${\small{\tt{\implies{ \dfrac{1}{3} \bigg(x^2 + 3x - 9x - 27 \bigg)}}}}$

${\small{\tt{\implies{ \dfrac{1}{3} \bigg\lbrace x(x+3) -9(x+3) \bigg\rbrace }}}}$

${\small{\tt{\implies{\dfrac{1}{3} \bigg\lbrace (x-9)(x+3) \bigg\rbrace }}}}$

${\small{\tt{\implies{ \red{(x-9)(x+3)}}}}}$

So , factors of (1/3)x² - 2x - 9 are (x-9)(x+3).

${\Large{\fcolorbox{navy}{magenta}{\boxed{ \frak{(x-9)(x+3)}}}}}$