Question

30) Find the area of triangle whose sides are 18 cm and 10 cm with perimeter as 42 cm.​

Answer 1

Answer:

Area of triangle =70cm²

Step-by-step explanation:

10+18+C=42

28+C=42

C=42-28

C=14

Area of triangle=1/2×10×14

=70cm²

Answer 2

first side of triangle=18

second= 10

third= ?

a+b=18+10=28cm

peremeter of triangle

a+b+c=42cm

hence,

c=42-28cm=14cm

also,

S= a+b+c ÷2 =42÷2=21

Area of triangle =

$\sqrt[21]{11}$

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