30.
For reaction
A + 2B = 2C
Initally 2 mole of A and B are taken in 10 lit flask
at equilibrium 1 mole of C is formed then calculate
Kc for given reaction :-
(1) 6.66 (2) 3.33 (3) 2.22 (4) 1.11
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The value of the equilibrium constant is 6.6
Explanation:
Initial moles of A = 2 mole
Initial moles of B = 2 mole
Moles of C at equilibrium= 1 mole
Volume of container = 10 L
Initial concentration of B=
Initial concentration of B=
equilibrium concentration of C = [/tex]
The given balanced equilibrium reaction is,
Initial conc. 0.2 M 0.2 M 0
At eqm. conc. (0.2-x) M (0.2-2x) M (2x) M
The expression for equilibrium constant for this reaction will be,
we are given : 2x= 0.1 M
x= 0.05 M
Now put all the given values in this expression, we get :
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