Question

30. From the extremities of a ship 500 ft. long the angles which the
direction of a buoy makes with that of the ship are 60° and 75º. Find the
distance of the buoy from the ship, having given that cot 75º = 278
Ans. 125 (V3 + 3) ft.​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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