30 g of metal reacts with 25 g dilute HCl liberated 5li H2 gas at 27 oC and 0.5 atm pressure . what is its equivlnt weight ?
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Wt. of metal = 30 g , wt. HCl=25g , vol of H2= 5 l , T= 27+273 = 300 K , P=0.5atm
p1v1/t1=p2v2/T2 = x2= 0.5*5*273/300 l at stp
Eq.m = wt.m*11.2/vol.of H2 at STP = 3*300*11.2/2.5*273 = 147.7
p1v1/t1=p2v2/T2 = x2= 0.5*5*273/300 l at stp
Eq.m = wt.m*11.2/vol.of H2 at STP = 3*300*11.2/2.5*273 = 147.7
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