30 g of nacl is present in 50 ml of water find out normality of solution
Answers
Let's start off with the equation for molarity:
We are given the molarity and the volume of solution. The only issue is that the volume is given in mL instead of L. This issue can be fixed by using the following conversion factor:
1000 m L = 1 L
Therefore, if we divide 50mL by 1000mL we will obtain a value of 0.05L.
Next, the equation has to be rearranged to solve for the moles of solute:
Moles of solute = Molarity
×
Liters of solution
Now, multiply 0.360 M by 0.05:
0.360 mol
1 L
×
0.05 L
=
0.018 mol
To obtain the mass of solute, we will need to the molar mass of NaCl, which is 58.44 g/mol:
Finally, multiply the number of moles by 58.44 g/mol
0.018
mol
×
58.44
g
1
mol
Boom, here it is:
1.05
g
Answer:
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Explanation:
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