Question

30 g of urea is dissloved in 90 g of water. the mole fraction of urea in the solution​

Answer 1

Given:

30 g of urea is dissolved in 90 g of water.

To Find:

the mole fraction of urea in the solution​

Solution:

The formula of mole fraction is as follows:-

Mole fraction of a component = Number of moles of that component / Total number of moles in the solution

So, we first need to determine the number of moles of each component:-

Number of moles = Given mass / Molar mass

Molar mass of urea and water is 60g/mol and 18g/mol respectively.

Number of moles of urea = (30 / 60) = 0.5

Number of moles of water = (90 / 18) = 5

Mole fraction of Urea = Number of moles of urea / (Number of moles of urea + Number of moles of water)

= 0.5 / (0.5 + 5)

= (0.5 / 5.5) = 0.09

Hence, the mole fraction of urea in the solution is 0.09.