Question

30 g of urea is dissolved in 500ml of solution What is thé osmotic pressure of the solution at 300k

Answer 1

Answer : The osmotic pressure of solution is, 24.63 atm.

Solution : Given,

Mass of solute (urea) = 30 g

Molar mass of urea = 60 g/mole

Volume of solution = 500 ml = 0.5 L

Temperature of solution = 300 K

Formula used for osmotic pressure :

$\pi=\frac{nRT}{V}\\\\\pi=\frac{wRT}{MV}$

where,

$\pi$ = osmotic pressure

V = volume of solution

R = solution constant  = 0.0821 Latm/moleK

T= temperature of solution = 300 K

M = molar mass of solute (urea)

w = mass of solute (urea)

Now put all the given values in the above formula, we get the osmotic pressure of the solution.

$\pi=\frac{(30g)\times (0.0821Latm/moleK)\times (300K)}{(60g/mole)\times (0.5L)}=24.63atm}$

Therefore, the osmotic pressure of solution is, 24.63 atm.