Question

30 g of water at 60°C is mixed with 20 g of water at 10°С. Find the resulting
temperature of the mixture.
​

Answer 1

Answer:

Heat lost by the hot water=Heat gained by the cold water.

m

1

cΔT

1

=m

2

cΔT

2

20(60−T)=60(T−20)

60−T=3T−60

4T=120

T=30

o

C