Question

30 grams of magnesium reacts with the 30 grams of dioxygen.
1) calculate the mass of MgO formed
2)identify the limiting reagent and also the give the mass of the reagent remaining with reacting​

Answer 1

Answer:

80.6g

Explanation:

2Mg+O

2

→2MgO

The atomic masses of Mg and O are 24.3 g/mol and 16 g/mol respectively.

The molar mass of MgO=24.3+16=40.3g/mol

Number of moles is the ratio of mass to molar/atomic mass.

48.6 g of Mg corresponds to

24.3

48.6

=2 moles

64 g of O2 corresponds to

2×16

64

=2 moles

2 moles of Mg will react with 1 mole of O

2

to produce 2 moles of MgO.

Since 2 moles of O

2

are present, O

2

is excess reagent and Mg is limiting reagent.

2 moles of Mg will give 2 moles of MgO.

Mass of MgO =2×40.3=80.6g

Answer 2

Answer:

see attachment for explanation

Explanation:

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