Question

30 grams of saturated solution on evaporation gives a rescue of 5 grams of solute the solubility of solute is ​

Answer 1

Explanation:

weight of salt = 90 gram,

solubility = 50

sing formula

solubility of solute =

weightofsolventinsaturatedsolution

weightofsoluteinsaturatedsolution

×100

or 50=

weightofsolventinsaturatedsolutio

90gm

×100

so weight of solvent in saturated solution =

50

90gm

×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.

Answer 2

S = 20

Explanation:

Given ,

wt. of solute - 5gms

wt. of solution - 30gms

wt. of solvent = (wt. of solution - wt. of solute)

= 25gms

S= (wt. of solute / wt. of solvent) * 100

S = (5 / 25) *100

S = 1/5 * 100

S = 20