30. If sec 0 + tan 0 = p,
then find the value of cosec 0.
Answers
Answered by
1
sec 0=p-tan 0
As cosec 0=1/sec 0
Therefore cosec 0=1/(p-tan 0)
Answered by
0
Answer:
Given :
sec A + tan A = p
I am replacing p by ' k '
sec A + tan A = k
We know :
sec A = H / B & tan A = P / B
H / B + P / B = k / 1
H + P / B = k / 1
So , B = 1
H + P = k
P = k - H
From pythagoras theorem :
H² = P² + B²
H² = ( H - k )² + 1
H² = H² + k² - 2 H k + 1
2 H k = k² + 1
H = k² + 1 / 2 k
P = k - H
P = k² - 1 / 2 k
Now write k = p we have :
Base = 1
Perpendicular P = P² - 1 / 2 P
Hypotenuse H = P² + 1 / 2 P
Value of cosec A = H / P
cosec A = P² + 1 / 2 P / P² - 1 / 2 P
cosec A = P² + 1 / P² - 1
Therefore , we got value .
Similar questions