Question

30. If the smallest side of a trapezium is 10 m and distance between the two parallel sides of the trapezium
is 20 m and also its area is 480
2
, then find the other side of the trapezium.

Answer 1

Answer:

hi

Step-by-step explanation:

the one side=10m

let be another side=y

height=20m

area=1/2h(sum of parallel)=480

1/2x20x(10+y)=480

10(10+y)=480

10+y=48

y=38

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Answer 2

Answer:

Other or longer side is of 38 metre.

Step-by-step explanation:

let longer side be x.

Area of Trapezium=1/2×height×sum of parallel sides.

480m²=1/2×20m×(10+x)m

480m²=100m+10x

480m²-100m=10x

380m²=10x

380m²/10=x

38m=x