Question

30
If the sum of the zeroes of the
polynomial p(x) = (k2 - 14) x2 - 2x -
12 is 1, Then the value of k=
--
(1 Point)
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Answer 1

Answer:

I hope it will help you:

(K2-14)×2-2x-12=1

2k2-28-2x-12=1

2k2-2x-40=1

D=b2-4ac

D=1

a=2k,b=-2,and c=-40

b2-4ac=1

(-2)2-(4×2k-40)=1

-4-(-320k)=1

-4+320k=1

320k=5

K=5/320

K=1/64

Explanation: