Math, asked by akakshatha110, 8 days ago

30. In a binomial distribution the sum of p + q is​

Answers

Answered by bhuvanakruthi61
1

Answer:

Correct option is

A

17

Let n and p the parameters of distribution. So,

q=1−p as p+q=1

Mean + Variance =

3

25

np+npq=

3

25

np=

3(1+q)

25

Mean × Variance =

3

50

n

2

p

2

q=

3

50

[

3(1+q)

25

]

2

.q=

3

50

25q=6(1+q)

2

6q

2

−13q+6=0

(2q−3)(3q−2)=0

q=

2

3

or q=

3

2

Since, q≤1, so, q=

3

2

p=1−q=

3

1

Answered by pulakmath007
0

In a binomial distribution the sum p + q = 1

Given :

A binomial distribution

To find :

The sum p + q

Solution :

Step 1 of 2 :

Define binomial distribution

If a trial is repeated n times and p is the probability of a success and q that of failure then the probability of r successes is

 \displaystyle \sf{  \sf{P(X=r) =  \:  \: }\large{ {}^{n} C_r}\:  {p}^{r}  \:  \:  {q}^{n - r} } \:  \:  \:  \:  \: where \: q \:  = 1 - p

Step 2 of 2 :

Find the value of p + q

In a binomial distribution

p = probability of success

q = probability of failure

Thus p + q = 1

Hence the value of p + q = 1

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